A ball of mass 0.190 kg w/ a velocity of 1.59î m/s meets a ball of mass 0.301 kg w/ a velocity of -0.393î m/s in a head-on elastic collision?
(a) Find their velocities after the collision.
(b) Find the velocity of their center of mass before and after the collision.
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m1u1 + m2u2 = m1v1 + m2v2
0.19*1.59 + 0.301*(-0.393) = 0.19*v1 + 0.301*v2
0.3021 - 0.118293 = 0.19v1 + 0.301v2
0.183807 = 0.19v1 + 0.301v1 ----(1)
v2 - v1 = u1 - u2
v2 - v1 = 1.59 - (-0.393)
v2 - v1 = 1.983 -----(2)
Solve (1) and (2). You will get v1 and v2