Ola Elizabeth
área do triangulo
-1 -1 1
6 -3 1
4 -10 1
det = ¦3 - 60 - 4 + 12 - 10 + 6¦ = 53
area = det/2 = 53/2
lado AC
L² = (-1 - 4)² + (-1 + 10)² = 25 + 81 = 106
L = √106
area
L*h/2 = 53/2
√106*h = 53
h = 53/√106 = 53*√106/106 = √106/2
pronto
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Ola Elizabeth
área do triangulo
-1 -1 1
6 -3 1
4 -10 1
-1 -1 1
6 -3 1
det = ¦3 - 60 - 4 + 12 - 10 + 6¦ = 53
area = det/2 = 53/2
lado AC
L² = (-1 - 4)² + (-1 + 10)² = 25 + 81 = 106
L = √106
area
L*h/2 = 53/2
√106*h = 53
h = 53/√106 = 53*√106/106 = √106/2
pronto