Can you simplify the above problem and explain please?
Thank you :)
(2x^2 - 5x - 3)/(x - 3)
= (2x^2 + x - 6x - 3)/(x - 3)
= [(2x^2 + x) - (6x + 3)]/(x - 3)
= [x(2x + 1) - 3(2x + 1)]/(x - 3)
= (2x + 1)(x - 3)/(x - 3)
= 2x + 1
Find the factors such that the product of the factors is the trinomial
2x^2 - 5 - 3
This can be done by trial and error and checked using the FOIL method of simplifying polynomials.
(2x + 1) (x - 3)
Multiply using the FOIL method to confirm (check and test).
2x x x = 2x^2
2x x -3 = -6x
1 x x = 1x
1 x -3 = -3
2x^2 - 6x + 1x - 3
2x^2 - 5x - 3
Therefore:
(2x + 1) (x - 3)/(x - 3)
Reduce the expression by cancelling out the common factor of (x - 3) from the numerator and denominator.
(2x + 1)
Remove the parentheses around the expression 2x + 1.
The answer is:
2x + 1
(X-3)/(2X^2-5X-3)
answer: (-2X-1)
To check your work:
If you multiply (-2X-1)(X-3)= -2X^2+5X=3
Then multiply by -1 and that will give you (2X^2-5X-3) which was what you were were trying to simplify
2x+1.
(2x+1)(x-3)=2x^2-6x+x-3
=2x^2-5x-3
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Verified answer
(2x^2 - 5x - 3)/(x - 3)
= (2x^2 + x - 6x - 3)/(x - 3)
= [(2x^2 + x) - (6x + 3)]/(x - 3)
= [x(2x + 1) - 3(2x + 1)]/(x - 3)
= (2x + 1)(x - 3)/(x - 3)
= 2x + 1
(2x^2 - 5x - 3)/(x - 3)
Find the factors such that the product of the factors is the trinomial
2x^2 - 5 - 3
This can be done by trial and error and checked using the FOIL method of simplifying polynomials.
(2x + 1) (x - 3)
Multiply using the FOIL method to confirm (check and test).
2x x x = 2x^2
2x x -3 = -6x
1 x x = 1x
1 x -3 = -3
2x^2 - 6x + 1x - 3
2x^2 - 5x - 3
Therefore:
(2x + 1) (x - 3)/(x - 3)
Reduce the expression by cancelling out the common factor of (x - 3) from the numerator and denominator.
(2x + 1)
Remove the parentheses around the expression 2x + 1.
The answer is:
2x + 1
(X-3)/(2X^2-5X-3)
answer: (-2X-1)
To check your work:
If you multiply (-2X-1)(X-3)= -2X^2+5X=3
Then multiply by -1 and that will give you (2X^2-5X-3) which was what you were were trying to simplify
2x+1.
(2x+1)(x-3)=2x^2-6x+x-3
=2x^2-5x-3