Verified answer

^5 √ 32x^6y^2w^10 =

^5 √ 2^5x^6y^2w^10 =

(2 * x w^2) ^5 √xy^2 =

2w^2 ^5√xy^2

Simplify this? Omg... I hate my life right now...

5^rad(32x^6y^2w^10)

I'm assuming the numbers are 32x^6, y^2, w^10 right?

Do them separately....

rad32x^6 = [rad(32)]^rad(6)] =

[rad(4) times rad(2) times rad(2) times rad(2)]^ 3

rad(y^2) = y

rad(w^10) = w^10

5^ [{4(rad 2)x}^3 times y times w^5]

Hmmm further simplification would be...

lets assume [{4(rad 2)x}^3 times y times w^5] = K

[ln(5)] times k would also be an answer.

But to tell you the truth I'm not sure lmao!

Goodluck!