Multiplication is commutative... so I dont see how zw is any different from wz. The product of z and w is being added to itself. And an imaginary component will exist in the product.
If a,b,c,d are real, then wz = zw = (ac - bd) + (ad + bc)i...
and so zw + wz = 2(ac - bd) + 2(ad + bc)i
And Im unsure what you mean by a,b,c,d in the set of IR. What is IR?
Answers & Comments
Verified answer
Multiplication is commutative... so I dont see how zw is any different from wz. The product of z and w is being added to itself. And an imaginary component will exist in the product.
If a,b,c,d are real, then wz = zw = (ac - bd) + (ad + bc)i...
and so zw + wz = 2(ac - bd) + 2(ad + bc)i
And Im unsure what you mean by a,b,c,d in the set of IR. What is IR?