緊急
求快 拜托
(-3)^2+(-3)a-15=0
9-3a-15=0
a= - 2
x^2-2x-15=0
(x-5)(x+3)=0
Ans: a = -2, 另一根為 5
因為-3是方程式的根,所以帶入方程式等號會成立
x^2+(-3)a-15=0,a=-2
所以方程式為x^2-2x-15=0
x=-3or5
所以另一根是5
Sub. -3 into the equation: (-3)^2 +a(-3) - 15 = 0 9 - 3a - 15 = 0 a = -2. So the equation is x^2 - 2x - 15 = 0. (x +3)(x - 5) = 0 the other root is 5
put x=-3 in the x^2+ax-15=0
(-3)^2-3a-15=0
a=-2
x=5 or x=-3
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Verified answer
(-3)^2+(-3)a-15=0
9-3a-15=0
a= - 2
x^2-2x-15=0
(x-5)(x+3)=0
Ans: a = -2, 另一根為 5
因為-3是方程式的根,所以帶入方程式等號會成立
x^2+(-3)a-15=0,a=-2
所以方程式為x^2-2x-15=0
x=-3or5
所以另一根是5
Sub. -3 into the equation: (-3)^2 +a(-3) - 15 = 0 9 - 3a - 15 = 0 a = -2. So the equation is x^2 - 2x - 15 = 0. (x +3)(x - 5) = 0 the other root is 5
put x=-3 in the x^2+ax-15=0
(-3)^2-3a-15=0
a=-2
x^2-2x-15=0
x=5 or x=-3