a million) 4-3x<=8+x 4+8<=x+3x 12<=4x 3<=x or l [3,plus infinity) 2) 3x-3>-x+a million 3x+x>a million+3 4x>4 x>a million or (a million, plus infinity) 3) 3(x-a million)=<4x 3x-3<=4x -3<=x or [-3, plus infinity) 4)a million/2x<x+a million -a million<x/2 -2<x or (-2, plus infinity) 5)-a million/2x>a million-x x/2>a million x>2 or x interior the era (2, plus infinity) s
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Verified answer
3x + 2 > −4
=> 3x > -6
=> x > -2
2x − 1 < 5
=> 2x < 6
=> x < 3
Therefore c because -2 < x < 3
a million) 4-3x<=8+x 4+8<=x+3x 12<=4x 3<=x or l [3,plus infinity) 2) 3x-3>-x+a million 3x+x>a million+3 4x>4 x>a million or (a million, plus infinity) 3) 3(x-a million)=<4x 3x-3<=4x -3<=x or [-3, plus infinity) 4)a million/2x<x+a million -a million<x/2 -2<x or (-2, plus infinity) 5)-a million/2x>a million-x x/2>a million x>2 or x interior the era (2, plus infinity) s
E: drop that ******* class because that sounds like HELL
The answer is E for sure.