y = mx + b

m = 6

b = 5

y = 6x + 5

...........................

y = mx + b

m = -1/8

y = 0

x = -5

0 = -(1/8) * -5 + b

0 = 5/8 + b

-5/8 = b

y = (-1/8)x - 5/8

8y = -x - 5

x + 8y = -5

The equation of a line with slope m and y-intercept (0,b) is y = mx + b. So, for m=6 and b=5, the equation would be y=6x+5.

The equation of a line with slope m passing through (x1,y1) is y-y1=m(x-x1). So for m=-1/8 and (x1,y1)=(-5,0), the equation would be:

y - 0 = (-1/8)[x - (-5)]

Rewriting it in the specified form, we have:

y = -1/8(x + 5)

-8y = x + 5

-x - 8y = 5

x + 8y = -5

I hope that helps! :)