Is it to the backside of 3??? log3[2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d] Who ever thumbed me down is an absolute fool! You gu2daf79c78ca0e616d0a538dfa334f3ds under could desire to circulate returned to college and study maths returned. You such nut heads. that won't be able to be conceivable until eventually it replaced into meant to be... log 3 x*(y^2)*(z^4) - x*(y^2)*(z^4) log 3 x*(y^2)*(z^4) - x*(y^2)*(z^4) log 3 x*(y^2)*(z^4)
Answers & Comments
Verified answer
log_3(x) – 2 log_3(y) – 4 log_3(z)
log_3(x) – log_3(y^2) – log_3(z^4) ← power rule
log_3(x / (y^2 z^4)) ← quotient rule
matches none of the given choices.
is the original expression correct?
if it was supposed to be
1/2 log_3(x) – 2 log_3(y) – 4 log_3(z)
then
log_3(√(x) / (y^2 z^4))
probably matches the 1st given choice.
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Is it to the backside of 3??? log3[2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d2daf79c78ca0e616d0a538dfa334f3d] Who ever thumbed me down is an absolute fool! You gu2daf79c78ca0e616d0a538dfa334f3ds under could desire to circulate returned to college and study maths returned. You such nut heads. that won't be able to be conceivable until eventually it replaced into meant to be... log 3 x*(y^2)*(z^4) - x*(y^2)*(z^4) log 3 x*(y^2)*(z^4) - x*(y^2)*(z^4) log 3 x*(y^2)*(z^4)