it can be -2x + 3y = 7
find the slope and then find your 'b':
get the given equation into slope intercept form : y=mx + b
-2x + 3y = -4
3y = 2x - 4
y = 2/3x - 4/3
y = mx + b,
m = 2/3, b = -4/3
the slope is m and m is 2/3, so the slope is 2/3.
our line has to be parallel so it needs to have the same slope as the first line, so it also needs a slope of 2/3.
y = mx + b
m = 2/3
y = 2/3(x) + b
our point is (1,3) so plug that in and find b to get the final equation:
3 = 2/3(1) + b
3 = 2/3 + b
3 - 2/3 = b
b = 2 1/3
so in our line with slope of 2/3, our b is 2 1/3,
y = 2/3x + 2 1/3
y = 2/3x + 7/3
drghrth45uj45t4534
:-
- 2x + 3y = - 4
y = (2/3) x - 4/3 ______equation of given line.
Gradient is 2/3
y - 3 = (2/3) ( x - 1 )
y = (2/3) x + 7/3________equation of parallel line
A line parallel to the line whose equation is -2x + 3y = -4
and passes through the point (1, 3):
-2x + 3y = 7
or
2x - 3y = -7
-2x+3y=-2(1)+3(3)
-2x+3y=7 or more formally 2x-3y=-7
-2x+3y = -4 ⇒ y = (2/3) x - (4/3)
The equation of the line parallel to -2x+3y = -4 and passing through (1,3) is
y - 3 = (2/3)(x - 1)
y = (2/3) x + 2...................ANS
-2(1) + 3(3) = a for some a. Solve for a to find the parallel line through (1, 3).
-2 + 9 = a
a = 7
any parallel line
-2x+3y = b
plug in (1,3)
-2(1) + 3(3) = b
-2 + 9 = b
b = -7
-2x + 3y = -7
- 2(1) + 3 ( 3 ) = 7....thus - 2x + 3y = 7
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Answers & Comments
it can be -2x + 3y = 7
find the slope and then find your 'b':
get the given equation into slope intercept form : y=mx + b
-2x + 3y = -4
3y = 2x - 4
y = 2/3x - 4/3
y = mx + b,
m = 2/3, b = -4/3
the slope is m and m is 2/3, so the slope is 2/3.
our line has to be parallel so it needs to have the same slope as the first line, so it also needs a slope of 2/3.
y = mx + b
m = 2/3
y = 2/3(x) + b
our point is (1,3) so plug that in and find b to get the final equation:
3 = 2/3(1) + b
3 = 2/3 + b
3 - 2/3 = b
b = 2 1/3
so in our line with slope of 2/3, our b is 2 1/3,
y = mx + b
m = 2/3
b = 2 1/3
y = 2/3x + 2 1/3
y = 2/3x + 7/3
drghrth45uj45t4534
:-
- 2x + 3y = - 4
3y = 2x - 4
y = (2/3) x - 4/3 ______equation of given line.
Gradient is 2/3
y - 3 = (2/3) ( x - 1 )
y = (2/3) x + 7/3________equation of parallel line
A line parallel to the line whose equation is -2x + 3y = -4
and passes through the point (1, 3):
-2x + 3y = 7
or
2x - 3y = -7
-2x+3y=-2(1)+3(3)
-2x+3y=7 or more formally 2x-3y=-7
-2x+3y = -4 ⇒ y = (2/3) x - (4/3)
The equation of the line parallel to -2x+3y = -4 and passing through (1,3) is
y - 3 = (2/3)(x - 1)
y = (2/3) x + 2...................ANS
-2(1) + 3(3) = a for some a. Solve for a to find the parallel line through (1, 3).
-2 + 9 = a
a = 7
-2x + 3y = 7
any parallel line
-2x+3y = b
plug in (1,3)
-2(1) + 3(3) = b
-2 + 9 = b
b = -7
-2x + 3y = -7
- 2(1) + 3 ( 3 ) = 7....thus - 2x + 3y = 7