When resistors 1 and 2 are connected in series, the equivalent resistance is 22.7 Ω.?
When resistors 1 and 2 are connected in series, the equivalent resistance is 22.7 Ω. When they are connected in parallel, the equivalent resistance is 4.45 Ω. What are (a) the smaller resistance and (b) the larger resistance of these two resistors?
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Verified answer
Use System Of Equations:
R1 + R2 = 22.7
1/R1 + 1/R2 = 1/4.45
(R1)^2 - 22.7R1 + 101.02 = 0
Quadratic Formula:
Bigger Resistor (R1) = 16.62 ohms
Smaller Resistor (R2) = 6.08 ohms
This requires simultaneous equations.
First equation: R1 + R2 = 22.7
Second equation: R1*R2/(R1+R2) = 4.45
Put your math skills to work.