When 47.6J of heat are added to 13.6g of a liquid, its temperature rises by 1.76∘C?
what is heat capacity?
so i am figuring that 47.6j=q the heat
13.6g=m the mass
but idk what the temp change is or deltaT is for the initial and final temp. help?
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The temp change is 1.76 C. We don't care what it started at or ended at, just how much.
47.6 J = (13.6 g) (1.76 C) (x)
x = 1.99 J/g C
The statement "its temperature rises by 1.76 C" means delta-T is 1.76. That's the change of temperature. You don't need the initial and final, you're given the delta.