and if i were to graph the inverse function, is it possible to do that by finding the y=x of the first function?
thank you.
f(x)=√(x - 3)
y =√(x - 3)
change variables
x = √(y - 3)
square
x^2 = y - 3
get y on its own
y = x^2 + 3
f^-1(x) = x^2 + 3
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Verified answer
f(x)=√(x - 3)
y =√(x - 3)
change variables
x = √(y - 3)
square
x^2 = y - 3
get y on its own
y = x^2 + 3
f^-1(x) = x^2 + 3