what would be the derivative of (θ^2+cos4θ) with respect to θ.....
now its asking me for the second derivative..
2 * θ - 4 * sin(4 * θ)
f''(θ) = f'(2θ - 4sin4θ) = 2 - 16cos4θ.
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2 * θ - 4 * sin(4 * θ)
f''(θ) = f'(2θ - 4sin4θ) = 2 - 16cos4θ.