What mass of water at 25.0°C must be allowed to come to thermal equilibrium with a 4.60 kg?
What mass of water at 25.0°C must be allowed to come to thermal equilibrium with a 4.60 kg gold bar at 100°C in order to lower the temperature of the bar to 50.0°C?
More Questions From This User See All
Answers & Comments
Verified answer
heat gained by water = heat lost by gold
heat gained by water = mass water x 4186J/kg/C x (100-25)C
heat lost by gold = 4.6kg x 126J/kg/C x(100-50)C = 28,980J
mass water x 4186J/kg/C x 75C = 28,980J
mass water = 0.09kg