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What is the volume of 0.32 moles of carbon dioxide gas at 16°C and 752 mmHg
Use the ideal gas law: PV = n RT
First, you must convert units:
P = 752 mm Hg / 760 mmHg/atm = 0.989 atm
T = 16 + 273 = 289 K
Then,
PV = n RT
0.989 atm (V) = 0.32 mol X 0.0821 Latm/molK X 289 K
V = 7.68 L
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Verified answer
Use the ideal gas law: PV = n RT
First, you must convert units:
P = 752 mm Hg / 760 mmHg/atm = 0.989 atm
T = 16 + 273 = 289 K
Then,
PV = n RT
0.989 atm (V) = 0.32 mol X 0.0821 Latm/molK X 289 K
V = 7.68 L