Number of O atoms in 7.25×10−3mol Al(NO 3 ) 3 .?
Number of O atoms in 7.25×10−3mol Al(NO 3 ) 3 .
Al: 26.9815
N 14.0067
O 15.9994
Express your answer using three significant figures.
N=
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Number of O atoms in 7.25×10−3mol Al(NO 3 ) 3 .
Al: 26.9815
N 14.0067
O 15.9994
Express your answer using three significant figures.
N=
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Verified answer
Since you have 7.25×10^−3mol of Al(NO3)3 and you know there are 9 O atoms in every molecule of Al(NO3)3, it's simply
9 * 7.25*10^-3 mol = 0.06525 mol
or as a number, multiply it with avogadros constant and get: 9 * 7.25*10^-3 mol * 6.022*10^23 1/mol = 3.9294... * 10^22 ~= 3.93 * 10^22 atoms
(or 39.3 sixtillion atoms)