What is the true mass of water weighed at 24°C in the air if the apparent mass is 1.0346 + - 0.0002 g?
What is the true mass of water weighed at 24°C in the air if the apparent mass is 1.0346 + - 0.0002 g? The density of air is 0.0012 + - 0.0001g/mL and the density of balance weights is 8.0 + - 0.5g/mL.
More Questions From This User See All
Answers & Comments
Verified answer
This is a bouyancy question.
Wt H2O - Bh2o = WtBWs - BBWs = 1.0346g
The forces on the two sides of the scale ... well, they balance!
but the forces include bouyancy forces. If you recall your grade school physics (apparently you do not since here we are) the force of bouyancy is equal to the weight of the volume of displaced air.
So you need to determine delta V the difference in volume between the 2 sides of the balance
that volume of air is reducing the weight of the water (since we know the water will have a larger volume than the BWs (Balance Weights) when they have a density of 8.)
You'll need the density of water at 24C. Look it up. Then plug and chug.