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3x²-5x-15=0.....use quadratic formula.
a= 3; b = -5; c = -15
x=[ -b ± √(b²-4ac)]/2a
x = [--5±√((-5)²-4•3•-15)]/2•3
x = [5±√(25+180)]/6
x = 5±√(205)]/6
x = (5+√250)/6 and x = (5-√250)/6
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3x²-5x-15=0.....use quadratic formula.
a= 3; b = -5; c = -15
x=[ -b ± √(b²-4ac)]/2a
x = [--5±√((-5)²-4•3•-15)]/2•3
x = [5±√(25+180)]/6
x = 5±√(205)]/6
x = (5+√250)/6 and x = (5-√250)/6