Please shows your work so I understand how to get the answer.
if you don't know the notation, dy/dx is derivative of y with respect to x. also known as f ' (x).
Product Rule: states, given f(x)=g(x) * h(x) the dy/dx= d/dx g(x) * h(x) + d/dx h(x) * g(x)
back to the example.
dy/dx = d/dx(x^2 -2)(x^2 +3) + d/dx(x^2 +3)(x^2 -2)
take the derivative of: (x^2 -2) = 2x
dy/dx= 2x(x^2 +3) + d/dx(x^2 +3)(x^2 -2)
Take the derivative of (x^2 +3) = 2x
therefore
dy/dx = 2x(x^2 +3) + 2x(x^2 -2)
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if you don't know the notation, dy/dx is derivative of y with respect to x. also known as f ' (x).
Product Rule: states, given f(x)=g(x) * h(x) the dy/dx= d/dx g(x) * h(x) + d/dx h(x) * g(x)
back to the example.
dy/dx = d/dx(x^2 -2)(x^2 +3) + d/dx(x^2 +3)(x^2 -2)
take the derivative of: (x^2 -2) = 2x
dy/dx= 2x(x^2 +3) + d/dx(x^2 +3)(x^2 -2)
Take the derivative of (x^2 +3) = 2x
therefore
dy/dx = 2x(x^2 +3) + 2x(x^2 -2)