What is the remaining trig functions of Cotθ= -1/3 when csc<0 ?
tan Ө = - 3
If quadrant 2 :
sin Ө = 3 / √10
cos Ө = -1 / √ 10
if quadrant 4
cos Ө = 1 / √ 10
cotθ = −1/3
csc²θ = 1 + cot²θ = 1 + 1/9 = 10/9
cscθ = −√10/3
sinθ = 1/cscθ = −3/√10
cosθ = cotθ * sinθ = 1/√10
tanθ = 1/cotθ = −3
secθ = 1/cosθ = √10
never heard of scs
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tan Ө = - 3
If quadrant 2 :
sin Ө = 3 / √10
cos Ө = -1 / √ 10
if quadrant 4
sin Ө = 3 / √10
cos Ө = 1 / √ 10
cotθ = −1/3
csc²θ = 1 + cot²θ = 1 + 1/9 = 10/9
cscθ = −√10/3
sinθ = 1/cscθ = −3/√10
cosθ = cotθ * sinθ = 1/√10
tanθ = 1/cotθ = −3
cotθ = −1/3
secθ = 1/cosθ = √10
cscθ = −√10/3
never heard of scs