Verified answer

The Ksp for aluminum hydroxide is 3×10^-34 at 25C. That is a constant, which you can look up. You then need to ask, "What is the value of Qsp for this solution?"

Al(OH)3 <==> Al3+ + 3OH-

Qsp = [Al3+] [OH]³

Qsp = (1.40x10^-8) (4.2x10^-8)³

Qsp = 1.0x10^-30

Next, we compare Q to K. If Qsp = Ksp the system is in equilibrium. If Qsp is less than Ksp, then no precipitate will form. But since Qsp is greater than Ksp a precipitate will form.

[Al3+][OH-]^3 = (1.40 x 10^-8)(4.20 x10^-8)^3 = 1.037 x 10^-30

Precipitation will occur if for Al(OH)3, the Ksp < 1.037 x 10^-30

(c) i'm uncertain the variety you will comprehend this with merely one test, yet of right here salts {Cu(ClO4)2, LiClO4, Li3PO4, Cu3(PO4)2} the final is the least soluble and for this reason the single that would precipitate. So your answer is "Cu^2+, PO4^3-" (d) 3 Cu(ClO4)2(aq) + 2 Li3PO4(aq) ---> 6 LiClO4(aq) + Cu3(PO4)2(s)