What is the energy stored in an inductor of value 108 μH and current 20 mA?
What is the equation and how do I set it up
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What is the equation and how do I set it up
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Energy = (1/2)(L)(I²)
E =0.5*(108 x 10^-6)(2x 10^-2)² = 2.16 x 10^-08 joules
108 μH and current 20 mA. Energy=(1/2)(inductance)(current)^2 = (1/2)(108 x 10^-6)(20 x 10^-3)^2 = 2.16 x 10^-8 Joules
E=0.5Lx I^2= 0.5(108x10^-6) x(0.02)^2
=2.16x10^-8 (J)