normalize by multiplying by (6-√3) / (6-√3)
(6-√3) / [(6+√3)(6-√3)]
(6-√3) / 33
If we look at this as simple order of operation I will divide 1/6 first giving me .166 I then add the sqrt of 3 to this. The sqrt of 3 is 1,732.
So .166 + 1.732 = 1.898
1/(6+√3) = (6-√3)/((6+√3)(6-√3))
= (6-√3)/(6² - 3)
= (6-√3)/33
1.89871747424
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Verified answer
normalize by multiplying by (6-√3) / (6-√3)
(6-√3) / [(6+√3)(6-√3)]
(6-√3) / 33
If we look at this as simple order of operation I will divide 1/6 first giving me .166 I then add the sqrt of 3 to this. The sqrt of 3 is 1,732.
So .166 + 1.732 = 1.898
1/(6+√3) = (6-√3)/((6+√3)(6-√3))
= (6-√3)/(6² - 3)
= (6-√3)/33
1.89871747424