An x-intercept is a place where the graph crosses the x-axis. When the graph crosses the x-axis, y is zero. So basically you just need to solve the equation for x:
I'm assuming it's x squared and not x2 like you have it there.
y=x^2-x-20
Go to y= on you calc and type it in. Hit graph and look at where they intersect the x line so that y is 0. Or hit 2nd and graph to go to table. Look at where y is 0 and write down the x value.
a million.for x-intercept,positioned y=0 if y=(x^2)-x-20, then, the x-intercepts are,5,-4. 2.dy/dx=2x-4;at x=0,this equals to -4<0 subsequently,optimal value at dy/dx=0 ie., x=2 3.2(x^2)+5x+5 delta=(-15)^a million/2 subsequently imaginary roots.
Answers & Comments
An x-intercept is a place where the graph crosses the x-axis. When the graph crosses the x-axis, y is zero. So basically you just need to solve the equation for x:
y + 20 = x^2 − x
y = x^2 - x - 20
0 = x^2 - x - 20
0 = (x - 5)(x + 4)
0 = x - 5
5 = x
0 = x + 4
-4 = x
So the x-intercepts are -4 and +5.
graph it in your calculator.
one intercept is (-4,0) and the other is (5,0)
I'm assuming it's x squared and not x2 like you have it there.
y=x^2-x-20
Go to y= on you calc and type it in. Hit graph and look at where they intersect the x line so that y is 0. Or hit 2nd and graph to go to table. Look at where y is 0 and write down the x value.
a million.for x-intercept,positioned y=0 if y=(x^2)-x-20, then, the x-intercepts are,5,-4. 2.dy/dx=2x-4;at x=0,this equals to -4<0 subsequently,optimal value at dy/dx=0 ie., x=2 3.2(x^2)+5x+5 delta=(-15)^a million/2 subsequently imaginary roots.