A block of mass 20 kg slides up a frictionless plane inclined at 11 ◦ with the horizontal under the influence?
A block of mass 20 kg slides up a frictionless
plane inclined at 11
◦
with the horizontal under
the influence of a force of 170 N acting parallel
to the incline and up the incline.
The acceleration of gravity is 9.8 m/s
2
.
What is the acceleration of the block?
Answer in units of m/s
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Verified answer
Hello
the weight force acting parallel to the incline and down the incline is mg*sin11°
= 20*9.81*sin11° = 37.43 N.
The net force up and parallel to the incline is then 170 - 37.43 N = 132.6 N.
and acceleration = Force/mass = 132.6 N/20 kg = 6.63 m/s^2 <-- ans.
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