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1:8

since

no. of favourable outcomes=1

no. of possible outcomes = 8 .........since there are 8 letters

so probablity of picking c= 1/8 or 1:8

:P luks like i calculated the probability in case of odds just remove the c from the favourable outcomes

so odds are 1:7 sorry for the mistake

The Chances Are 1/8 COLORADO C O L O R A D O 1 2 3 4 5 6 7 8. Which The Percent Wise Is 12.5% .125 or 1/8 So 1:8

The probability of picking a "c" with a random choice is 1/8 = 12.5%. But that's not how "odds" are calculated. The "odds" of picking a "c" is the ratio of "correct" to "incorrect" choices.

In the word "Colorado" there is 1 choice that gives a correct answer, and 7 choices that do not.

The odds are 1:7.

Colorado has 8 letters. There's only 1 c in Colorado. Therefore the odds of "picking" a c in Colorado are 1 in 8, or:

1 : 8

8 letters 1 c 1:8

1:8

there are eight letters

one is a "c"

seven are not a "c"

odds are

1 : 7

probability is

1/8 = 12.5%

To be pedantic the odds of picking a 'c' in 'Colorado' are 0. There is no 'c', the word contains a 'C'

12.5 %, or 1:8