Use Newton’s method with the specified initial approximation to find the third approximation.?
Use Newton’s method with the specified initial approximation x1 to find x3, the third approximation to the root of the given equation. (Give your answer to four decimal places.)
x^3+2x-4=0 when x1=1
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here are the first four:
x(n) = x - f(x) / f ' (x)
x f(x) f ' (x)
1.00000000000000000 -1.00000000000000000 5.00000000000000000
1.20000000000000000 0.12800000000000000 6.32000000000000000
1.17974683544304000 0.00146837876922401 6.17540778721359000
1.17950905701288000 0.00000020009019508 6.17372484672624000
1.17950902460292000 0.00000000000000000 6.17372461735918000