battery and a 20-Ω resistor, what is the current through the 15-Ω resistor?
15 and 30 in parallel are equal to 15•30/45 = 10 ohms. Added to 20, that is 30 ohms total.
I = E/R = 9/30 = 0.3 amps. This divides through the parallel combination, and the part that goes through the 15 ohm is I = 0.3(30)/45 = 0.2 amps.
The answer is .2 A. You must be in a physics or electronics class and this is one of the easiest electrical questions you will come across so you better learn your stuff!
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15 and 30 in parallel are equal to 15•30/45 = 10 ohms. Added to 20, that is 30 ohms total.
I = E/R = 9/30 = 0.3 amps. This divides through the parallel combination, and the part that goes through the 15 ohm is I = 0.3(30)/45 = 0.2 amps.
The answer is .2 A. You must be in a physics or electronics class and this is one of the easiest electrical questions you will come across so you better learn your stuff!