help with equations of exponential functions 81b^4=45 b ≈ ??????
math
81b^4=45 dvide 81 and 45 by 9
b^4 = 5/9
b= 4√5 /√3
there are two ways to do this. you can take the natural log of both sides and then pull the four down. Or divide 45 by 81 and take that answer to tthe exponential of (1/4)
81 b^4 = 45 divide by 81
b^4 = .555.... inverse of the ^4 is ^(1/4)
b = .5555^(1/4)
b = .8633400214
chaeck answer:
81 * .863400214^ 4 = 45
The previous answer is wrong
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Verified answer
81b^4=45 dvide 81 and 45 by 9
b^4 = 5/9
b= 4√5 /√3
there are two ways to do this. you can take the natural log of both sides and then pull the four down. Or divide 45 by 81 and take that answer to tthe exponential of (1/4)
81 b^4 = 45 divide by 81
b^4 = .555.... inverse of the ^4 is ^(1/4)
b = .5555^(1/4)
b = .8633400214
chaeck answer:
81 * .863400214^ 4 = 45
The previous answer is wrong