*Trigonometry* Show that θ=77.7 In the equation: sec^2(θ/3 - 50)=1.2?
There are actually 2 answers to this equation but, I don't know how to get the second one, which is the one stated in my question. Just for the record, the first answer I got is 222.3.
How did my textbook get 77.7?
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sec(θ/3 - 50) = 1.2
cos(θ/3 - 50) = 0.913
θ/3 - 50 = +/- 24.1
The 77.7 answer comes from taking the negative angle.
I suspect there may be other answers from the negative square root, but I haven't gone into that.