I need to find the exact value of cos15° using radicals as needed
The half-angle formula states that cos (x/2) = +,- sqrt[(1+cos x)/2].
Since the angle of 15° is exactly half of 30° and the cos 30° is a common angle known to be sqrt(3)/2, you can use this fact along with the half-angle formula to get your answer.
cos 15° = sqrt[(1+sqrt(3)/2)/2]
cos 15° = sqrt[(1/2 + sqrt(3)/4]
cos 15° = [1+sqrt(3)]/[2*sqrt(2)]
cos15°=â[(1+cos30°)/2]
=â[{1+(â3)/2}/2]
=â[1/2+(â3)/4]
cos(a-b) =cos(a)cos(b) +sin(a)sin(b)
cos(45)=sin(45) =sqrt(2)/2
cos(30)=sqrt(3)/2
sin(30) = 1/2
cos(45-30) = sqrt(6)/4 + 1/4
cos (45-30) = ( sqrt (6) - 1 ) / 4
hope it helps
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Verified answer
The half-angle formula states that cos (x/2) = +,- sqrt[(1+cos x)/2].
Since the angle of 15° is exactly half of 30° and the cos 30° is a common angle known to be sqrt(3)/2, you can use this fact along with the half-angle formula to get your answer.
cos 15° = sqrt[(1+sqrt(3)/2)/2]
cos 15° = sqrt[(1/2 + sqrt(3)/4]
cos 15° = [1+sqrt(3)]/[2*sqrt(2)]
cos15°=â[(1+cos30°)/2]
=â[{1+(â3)/2}/2]
=â[1/2+(â3)/4]
cos(a-b) =cos(a)cos(b) +sin(a)sin(b)
cos(45)=sin(45) =sqrt(2)/2
cos(30)=sqrt(3)/2
sin(30) = 1/2
cos(45-30) = sqrt(6)/4 + 1/4
cos (45-30) = ( sqrt (6) - 1 ) / 4
hope it helps