Ans : 40 V

Solution:

First find the net resistance...in this case all the resistors are in series so add them up..you will get net resistance as 5000 ohms.

Then find the current through the circuit by using ohm's law.(i=V/R)

You will get the value of current as i=200V/5000 = 1/25 amp.

As all the resistors are in series, the current through each resistor is same.

So, the voltage drop across the 1000 ohm resistor is V = i(r) = (1/25)(1000) = 40 V

The total resistance will be sum of the resistance so it will be 50*10^2. So current is found out using v-ri. So i becomes 0.04. So voltage drop across the 1*1 0^3 is. 0.04 *10^3. Using v=ri and the answer will be 40v where i is current

Capacitive Reactance Xc = one million/(2?fC) Inductive Reactance X? = 2?fL Impedance Z = ?(R² + X²) the place X = X? – Xc area attitude ? = arctan (X/R) Xc, X?, Z are in ?, f is in Hz C in farads, L in Henrys Xc = one million / 2?(one hundred)(220µ) = 7.23 ohms (a) b) Z = ?(10² + 7.23²) = 12.3 ohms I = E/Z = 23/12.3 = one million.ninety 4 amps c) ? = arctan (7.23/10) = 35.9º

the answer is 40