The temperature of 2.7 kg of water is 34° C. To cool the water, ice at 0° C is added to it. The desired final?
The temperature of 2.7 kg of water is 34° C. To cool the water, ice at 0° C is added to it. The desired final temperature of the water is 11° C. The latent heat of fusion for water is 33.5 × 104 J/kg, and the specific heat capacity of water is 4186 J/(kg·C°). Ignoring the container and any heat lost or gained to or from the surroundings, determine how much mass m of ice should be added.
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From the law of thermodynamics Heat lost = Heat gained
Heat gained by fusion + Heat gained by water formed from melted ice = Heat lost by warm water
m * 33.5 × 10^4 + m * 11 * 4186 = 2.7 * (34 - 11) * 4186
m ( 381046) = 259950.6
m (mass of ice) = 0.682 KG