The ionization constant, Ka, for acetic acid is 1.76 × 10-5. What is the pH of a 0.0800 molar solution?
The ionization constant, Ka, for acetic acid, HC2H3O2, is 1.76 × 10-5. What is
the pH of a 0.0800 molar solution of this acid?
A. 2.01
B. 2.93
C. 4.75
D. 5.85
E. All the above
F. None of the above
I am not sure how to do this problem, could someone please explain to me how to do it?
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Verified answer
1.76 x 10^-5 = [(x)(x)] / 0.0800
x = 1.18659 x 10^-3 M (this is the hydrogen ion concentration, I kept some extra guard digits.
pH = 2.926 (pick answer choice B)
More discussion on how this type of calculation is done:
http://www.chemteam.info/AcidBase/Ka-Solving1.html