The angle of elevation from a point on level ground to the top of a pyramid is 45° 40'.?
From a point 73 meters furter back on the same horizontal line, the angle of elevation to the top of the pyramid is 27° 50'. Find the height of the pyramid to the nearest tenth of a meter.
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Letb D represent the top of the pyramid C the foot of pyramid Angle of elevation from B is 40degrees 40
mins and from A angle of elevation 27degrees 50 mins Distance AB = 73 metres BC = x CD = y
AC 73+x Must find value of y , the height Angle BDC = 44deg 20 min Angle ADC = 62deg 10 mins
x/y= tan 44deg 20 min x = y tan 44 deg 20 mins (x+73)/y=tan 62deg 10 mins )
x = ytan 62deg 10 mins - 73 therefore y tan 44deg 20 mins = y tan 62deg 10 mins - 73
y tan62deg 10min - ytan 44deg 20mins = 73 y ( tan 62deg 10min-tan 44deg20mins ) = 73
y = 73/( tan 62deg 10 mins - tan 44 deg 20 mins) y = 73/0.917001508 y = 79.60728458
y = 79.6 m