Please help! I'll give points or whatever to any right answer!
Btw sorry I'm new to yahoo...
I'm with the first responder....please preview your post before sending.
OK, Now we can work on the problem....
1. Draw yourself a picture of what is going on.
2. You know 2 sides of the triangle and the angle between them is 30+90 = 120
3. Use the Law of Cosines to find the displacement from the office to be = 99.84 km to 2 dp and if you're observing sig figs it would be 100 km.
4. Now you can use the Law of Sines to find the angle between the 43 km leg and the 99.8 km leg. 99.84/sin(120) = 80/sin(x) x = 43.94 degrees.
5. Now subtract x from 90 and you have your angle of displacement from east...
46.06 degrees to 2 dp.
not anything works in the process this if you do no longer state that her position of work and her position of displacement is at the comparable altitude, by way of actuality in navigation altitude additionally regarding calculation about tiers.
where's the rest of the question?
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I'm with the first responder....please preview your post before sending.
OK, Now we can work on the problem....
1. Draw yourself a picture of what is going on.
2. You know 2 sides of the triangle and the angle between them is 30+90 = 120
3. Use the Law of Cosines to find the displacement from the office to be = 99.84 km to 2 dp and if you're observing sig figs it would be 100 km.
4. Now you can use the Law of Sines to find the angle between the 43 km leg and the 99.8 km leg. 99.84/sin(120) = 80/sin(x) x = 43.94 degrees.
5. Now subtract x from 90 and you have your angle of displacement from east...
46.06 degrees to 2 dp.
not anything works in the process this if you do no longer state that her position of work and her position of displacement is at the comparable altitude, by way of actuality in navigation altitude additionally regarding calculation about tiers.
where's the rest of the question?