A 2.1 ✕ 103-kg car starts from rest at the top of a 4.3-m-long driveway that is inclined at 16° with the horiz?
A 2.1 ✕ 103-kg car starts from rest at the top of a 4.3-m-long driveway that is inclined at 16° with the horizontal. If an average friction force of 4.0 ✕ 103 N impedes the motion, find the speed of the car at the bottom of the
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According to the Conservation of Energy and Work:
Ui - W(friction) = Kf, U = mgdsin(theta), W(friction) = F(friction)d, and K = 0.5mv^2
Given that the mass of the car m is 2.1 * 10^3 kg, the length of the driveway d is 4.3 m, the angle of elevation theta is 16 degrees, and the force of friction F(friction) is 4.0 * 10^3 N,
mgdsin(theta) - F(friction)d = 0.5mv^2
v = sqrt[2(mgdsin(theta) - F(friction)d)/m]
Plug and chug and:
v = 2.617 m/s