The tangent is the inverse of the cotangent. This is 17/-2, -8.5. This angle is approximately 83˚ counter clockwise from the negative x-axis. To determine the rest of the functions, we need to determine the magnitude of the vector. We can use the Phathagorean theorem.
h = √(-2^2 + 17^2) = √293
The hypotenuse is approximately 17.1.
Sin θ = 17 ÷ √293
This is approximately 0.993.
Cos θ = √293 ÷ 17
This is approximately 0.12. The secant is the inverse of cosine
Sec θ = √293 ÷ 17
This is approximately 1.007. The cosecant is the inverse of the sine.
Cse θ = 17 ÷ √293
This is approximately 0.99. The website below is very helpful for this assignment.
Answers & Comments
The tangent is the inverse of the cotangent. This is 17/-2, -8.5. This angle is approximately 83˚ counter clockwise from the negative x-axis. To determine the rest of the functions, we need to determine the magnitude of the vector. We can use the Phathagorean theorem.
h = √(-2^2 + 17^2) = √293
The hypotenuse is approximately 17.1.
Sin θ = 17 ÷ √293
This is approximately 0.993.
Cos θ = √293 ÷ 17
This is approximately 0.12. The secant is the inverse of cosine
Sec θ = √293 ÷ 17
This is approximately 1.007. The cosecant is the inverse of the sine.
Cse θ = 17 ÷ √293
This is approximately 0.99. The website below is very helpful for this assignment.
http://www.softschools.com/math/calculus/the_6_tri...
cot = -2/17
tan = 1/cot = -17/2
cos = 2/√(17^2 +2^2) = 2/√293
sin = -17/√293
sec = 1/cos = √(293)/2
csc = 1/sin = -√(293)/17