3x^2 - 4x + 15
x = 3.
(5x^2 + 3) − (2x^2 + 4x − 12)
= 3x^2 - 4x + 15
(5x^2 + 3) - (2x^2 + 4x - 12) =
If you mean: (5x^2 +3) -(2x^2 +4x -12) = 3x^2 -4x +15
Is (5x2 + 3) − (2x2 + 4x − 12) = 0?
If yes, then you should get x = (2/3)±(√41i/3) where i=√-1
19 + 2 = eleventeen
i got 4
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Answers & Comments
3x^2 - 4x + 15
x = 3.
(5x^2 + 3) − (2x^2 + 4x − 12)
= 3x^2 - 4x + 15
(5x^2 + 3) - (2x^2 + 4x - 12) =
3x^2 - 4x + 15
If you mean: (5x^2 +3) -(2x^2 +4x -12) = 3x^2 -4x +15
Is (5x2 + 3) − (2x2 + 4x − 12) = 0?
If yes, then you should get x = (2/3)±(√41i/3) where i=√-1
3x^2 - 4x + 15
19 + 2 = eleventeen
i got 4