3. How much energy does it take to convert 0.508 kg ice at −20°C to steam at 250°C? Specific heat capacities:?
3. How much energy does it take to convert 0.508 kg ice at −20°C to steam at 250°C? Specific heat capacities: ice, 2.03 J/g · °C; liquid 4.2 J/g · °C; steam 2.0 J/g · °C, ΔHvap = 40.7 kJ/mol, ΔHfus = 6.02 kJ/mol.
Alright this one I know you have to find the amount of energy for each phase and then add them all up and then divide by 1000 to get in kj bc the answer comes out in j. I take all the numbers and they do not add up to the right answer. Anything would be helpful thankyou!!!!
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Don't add them up then divide by 1000.
1) 508 g of ice from -20 to 0 <--- answer in J
2) melt the 508 g of ice <--- answer in kJ
3) 508 g of liquid from 0 to 100 <--- answer in J
4) boil the 508 g of liquid <--- answer in kJ
5) 508 g of steam from 100 to 250 <--- answer in J
When you do the calculations, three of the answers are in J and two are in kJ. Divide the answers to 1, 3 and 5 by 1000, then add up all five to get the answer in kJ.
Here's a problem like yours that i wrote a number of years ago:
http://chemteam.info/Thermochem/Time-Temperature-G...