Verified answer

x+2y=4

x-y=3

Multiply the second equation by -1

x+2y=4

-x+y=-3

--------------Add

3y=1

y=1/3

Substitute -1/3 for y back into either original equation

x+2(1/3)=4

x+2/3=4

x=4-2/3

x=12/3-2/3

x=10/3

Check:x+2y=3

10/3+2(1/3)=4

12/3=4

4=4

x-y=3

10/3-1/3=3

9/3=3

3=3

Answers are correct

x - y =3 x=y+3

x+2y=4 (y+3)+2y=4

3y+3 =4 3(y+1)=4 y=4/3-1 y=1/3

x=1/3+3 x=10/3

x + 2y = 4

x – y = 3

x = y + 3

Now plug y + 3 in as x into the other equasion:

(y + 3) + 2y = 4

3y + 3 = 4

3y = 1

y = 1/3

Now plug 1/3 in as y back into the first one to find x:

x - 1/3 = 3

x = 4/3

So the answer is (4/3, 1/3) on a coordinate plane.

1. x+2y=-3 x-y=-12 = 2x+y=-15 y=x+12 2x+x+12=15 3x=3 x=1 y=13 i think 2. 3x+y=13 y=2x-2 3x+2x-2=13 5x=15 x=15 y=-2 i think the rest are practicall the same process dude.

Y=1/3

X=3 1/3

multiply the second equation by 2:

x + 2y = 4

2(x-y = 3)

x + 2y = 4

2x - 2y = 6

now add down:

3x = 10

x = 10/3

now replace the x into either equation:

x - y = 3

10/3 - y= 3

-y = -1/3

y = 1/3

Point of intersection: (10/3,1/3)

well isolate either variable in either equation

x = y + 3

plug it into other equation

y +3 + 2y = 4

3y = 1

y = 1/3

now x - 1/3 = 3

x = 3 1/3

multiply the second equation by 2 so you get

x+2y=4

2x-2y=6

then, simplify

3x=10

(the 2y and -2y cancel each other out, the you add the x and 2x to get 3x and you add the 4 and 6 to get 10)

then divide 10 by 3.

After you have your value for x, plug it into any of your first three equations to find y. good luck!

Multiply one of the two equations by negative one. I chose the second one.

x+2y=4

-x+y=-3

3y=1 and you can go from there. You know the y value, plug it into one of the equations to find the x value.