7 sin^2(theta) - 36 sin(theta) + 5 = 0

(7 sin^2(theta) - 35 sin(theta)) + (-sin(theta) + 5) = 0

7 sin(theta)(sin(theta) - 5) - 1(sin(theta) - 5) = 0

(7 sin(theta) - 1)(sin(theta) - 5) = 0

First factor: 7 sin(theta) - 1 = 0 ---> sin(theta) = 1/7, true for every theta = 2k(pi) + sin^-1(1/7), or 2k(pi) + pi - sin^1(1/7) radians if k is an integer.

Second factor: sin(theta) - 5 = 0 ---> sin(theta) = 5. False statement, hence no (real) solution possible here.

(sin(θ)-5)(7sin(θ)-1)=0

sinθ=1/7--->θ = sin^-1(1/7)+k2pi = ...calculator

and

θ = pi-sin^-1(1/7)+k2pi = ..