Plz show work
log[6](216)=-√x+16
is that -(√x) + 16 or -√(x+16) ?
remember that x^y = z is the same as log[base x](z) = y
so 6 to the power of what is 216? 6*6*6 = 216, thus y=3
log[6](216) = -√(x + 16)
3 = -√(x + 16)
-3 = √(x + 16)
(-3)² = (x + 16)
9 = x + 16
9 - 16 = x
x = -7
QED.
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Verified answer
is that -(√x) + 16 or -√(x+16) ?
remember that x^y = z is the same as log[base x](z) = y
so 6 to the power of what is 216? 6*6*6 = 216, thus y=3
log[6](216) = -√(x + 16)
3 = -√(x + 16)
-3 = √(x + 16)
(-3)² = (x + 16)
9 = x + 16
9 - 16 = x
x = -7
QED.