a) x > -1
b) x < -1
c) x < -3
d) x > -3
2. Solve for x: 3 − (2x − 5) < −4(x + 2)
a)x < −8
b) x > −8
c) x < −3
d) x > −3
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-3x + 3 < 6
-3x < 3
x < -1
3 - (2x - 5) < -4(x + 2)
8 - 2x < -4x - 8
2x < -16
x < -8
-3 x+3<6
- 3 x < 3
x>-1
3-2 x + 5<-4 x-8
8- 2 x <-4 x-8
2 x < -16
x<-8
-3x + 3 < 6 ?
-3x +3 -3 < 6 – 3
-3x/3 < 3/3
- X <1
x> -1 { multiplying both side by (-) signs got interchanged}
2) 3 â (2x â 5) < â4(x + 2)
3 -2x + 5 < -4x -8
8-2x < -4x -8
8 + 8 -2x +2x < -4x +2x -8 + 8
16 < -2x
from above
-2x > 16
-x > 8
hence , x < -8
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Verified answer
-3x + 3 < 6
-3x < 3
x < -1
3 - (2x - 5) < -4(x + 2)
8 - 2x < -4x - 8
2x < -16
x < -8
-3 x+3<6
- 3 x < 3
x>-1
3-2 x + 5<-4 x-8
8- 2 x <-4 x-8
2 x < -16
x<-8
-3x + 3 < 6 ?
-3x +3 -3 < 6 – 3
-3x < 3
-3x/3 < 3/3
- X <1
x> -1 { multiplying both side by (-) signs got interchanged}
2) 3 â (2x â 5) < â4(x + 2)
3 -2x + 5 < -4x -8
8-2x < -4x -8
8 + 8 -2x +2x < -4x +2x -8 + 8
16 < -2x
from above
-2x > 16
-x > 8
hence , x < -8