How can 40[(√2-2)/(2√2)] be simplified to 20(1-√2), show work please?
How can 40[(√2-2)/(2√2)] be simplified to 20(1-√2), show work please?
My teacher did this on the board, and i dont know how he got to the end result. I see that he cancelled 2's but i still dont understand ..
can somebody explain step by step?
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40 (√2 - 2)
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2√2
20 (√2 - 2)
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√2
20 √2 (√2 - 2)
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2
10 √2 (√2 - 2)
10 (2 - 2√2)
20 (1 - √2)
40[(√2-2)/(2√2)] =
(40/2)[(√2-2)/√2] =
20 [(√2/√2) - (2/√20] =
20 (1 - √2)
This is because √2 * √2 = 2.