3(2C – 5) = 45
3(2C – 5)/3 = 45/3
2C - 5 = 15
2C - 5 + 5 = 15 + 5
2C = 20
(2/2)C = 20/2
C = 10
Divide both sides by 3:
Add 5 to both sides:
Divide both sides by 2:
6c-15=45
6c=60
c=10
C=10
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Verified answer
3(2C – 5) = 45
3(2C – 5)/3 = 45/3
2C - 5 = 15
2C - 5 + 5 = 15 + 5
2C = 20
(2/2)C = 20/2
C = 10
Divide both sides by 3:
2C - 5 = 15
Add 5 to both sides:
2C = 20
Divide both sides by 2:
C = 10
6c-15=45
6c=60
c=10
C=10