√y+√y+7=7
taking √y on right side
√y+7 = 7 -√y
square on both sides
[(√y+7)]^2= [(7)-(√y)]^2
expanding
y + 14(√y) + 49 = 49 -14(√y) + y
canceling y and 49 on both side we get
14(√y) = - 14 (√y)
which is not true
OR
simply
taking right side to left side and leaving 0
√y+√y+7-7= 0
we have √y+√y = 0
or √y = -√y
Above equation is not ture
And just for your knowledge √0 is not 0 so this equation is also not ture if y = 0 or √y = 0 .:)
â0+â0+7=7
0+7=7
7=7
therefore, 'y' is 0. :D
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Verified answer
√y+√y+7=7
taking √y on right side
√y+7 = 7 -√y
square on both sides
[(√y+7)]^2= [(7)-(√y)]^2
expanding
y + 14(√y) + 49 = 49 -14(√y) + y
canceling y and 49 on both side we get
14(√y) = - 14 (√y)
which is not true
OR
simply
√y+√y+7=7
taking right side to left side and leaving 0
√y+√y+7-7= 0
we have √y+√y = 0
or √y = -√y
Above equation is not ture
And just for your knowledge √0 is not 0 so this equation is also not ture if y = 0 or √y = 0 .:)
â0+â0+7=7
0+7=7
7=7
therefore, 'y' is 0. :D