Solve Δ ABC if γ=90º, α=10º, and c=25cm
Thanks !!!
C=90°
A=10°
c=25cm
.
find B, a and b:
sum of angles:
A plus B plus C=180
B=180-(90 plus 10)= 80° answer (@_@)
sine laws:
a/sine A= b/sine B =c/sine C
a/sine 10=c/sine 90
sine 90°=1
a=c* sine 10
a=25*0.1736481
a=4.3412025 cm answer (@_@)
b=25*sine 80
b=25*0.9848077
b=24.6201924 cm answer (@_@)
since its a right triangle you can check it by pythagorean:
a^2 plus b^2=c^2 just apply the values
hope this helps (@_@)
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Answers & Comments
Verified answer
C=90°
A=10°
c=25cm
.
find B, a and b:
.
sum of angles:
A plus B plus C=180
.
B=180-(90 plus 10)= 80° answer (@_@)
.
.
sine laws:
a/sine A= b/sine B =c/sine C
.
a/sine 10=c/sine 90
.
sine 90°=1
.
a=c* sine 10
.
a=25*0.1736481
.
a=4.3412025 cm answer (@_@)
.
.
b=25*sine 80
.
b=25*0.9848077
.
b=24.6201924 cm answer (@_@)
.
.
since its a right triangle you can check it by pythagorean:
.
a^2 plus b^2=c^2 just apply the values
.
.
hope this helps (@_@)