Verified answer

Quando duas retas r e s são paralelas o coeficiente angular (m) é igual

r=5x+4y+2=0

m=-5/4

s=

(y-y0)=m(x-x0), onde x0 e y0 é o ponto A=(-2 -3)

[y-(-3)]=-5/4[x-(-2)]

y+3=-5/4(x+2)

4(y+3)=-5(x+2)

4y+12=-5x-10

5x+4y+22=0

5x+4y+2=0

4y=-5x-2

y=-5x/4-1/2 m=-5/4

y-(-3)=-5/4(x-(-2))

y+3=-5x/4-5/2

5x/4+y+3+5/2=0 vezes(4)

5x+4y+12+10=0

5x+4y+22=0

5x=-2-4y

x=-2-4y

5

5.(-2-4y) +4y +2 =0

5

-10-20y+ 4y +2=0

5

-10-20y+20+10=0 (corta + 10 e -10)(corta 5)

5

-20y+20=0

-20y=-20

-y=-20

20

-y=-1 .(-1)

y=1

x=-2-4y

5

x=-2-4.1

5

x=-2-4

5

x=-6

5

R(-6 ,1)

5